Standard-drink calculator
Smirnoff Ice: standard drinks & calories
0.8
standard drinks
99
calories (est.)
4.5%
ABV
A 11.2 oz bottle of Smirnoff Ice at 4.5% ABV contains about 0.5 fl oz of pure alcohol. Since one US standard drink is 0.6 fl oz of alcohol, that works out to about 0.8 standard drinks.
The math
standard drinks = volume × ABV% ÷ 0.6
11.2 oz × 4.5% ÷ 0.6 = 0.8
One US standard drink is 0.6 fl oz of pure alcohol. See what counts as a standard drink or the standard drink calculator to check any pour.
Frequently asked questions
How many standard drinks are in a Smirnoff Ice?
A 11.2 oz bottle of Smirnoff Ice at 4.5% ABV is about 0.8 US standard drinks. That's 0.5 fl oz of pure alcohol divided by 0.6 fl oz per standard drink.
How many calories are in a Smirnoff Ice?
Roughly 99 calories for a 11.2 oz bottle, estimated from its alcohol content plus typical carbohydrates for the style. This is a directional estimate, not a label-exact figure.